Solve. root of 4x+12-4=0 & x^2+8=17 & simplify root of 50 over root of 2?

Answer 1

4x +8 = 0
x = -2

x^2 = 9
x= +/-3

sqrt(50)/sqrt(2) = sqrt (25 *2) / sqrt 2 =
5 sqrt(2) /(sqrt(2)) = 5

Answer 2

Solve: sqrt(4x + 12) – 4 = 0

1. Get the radical by itself by adding 4 to both sides.
sqrt(4x + 12) = 4

2. Square both sides of the equation to eliminate the radical. --> (sqrt(x)) ^ 2 = x
4x + 12 = 16 (This is now a simple “solve for x” equation.)

3. Get the x term by itself by subtracting 12 from both sides.
4x = 4

4. Divide both sides by 4.
x = 1
The answer is x = 1.

Solve: (x ^ 2) + 8 = 17

1. Get the x term by itself by subtracting 8 from both sides.
x ^ 2 = 9

2. To eliminate the exponent, take the square root of both sides. (This is nice because 9 is a perfect square.)
x = 3
The answer is x = 3.

Solve: sqrt(50) / sqrt(2)

1. Break down the numerator. --> 50 = 2 * 25, so sqrt(50) = sqrt(2) * sqrt(25)
sqrt(50) / sqrt(2) = [sqrt(2) * sqrt(25)] / sqrt(2)

2. Cancel the sqrt(2) that is in both the numerator and denominator.
sqrt(25)

3. Simplify the perfect square.
sqrt(25) = 5
The answer is 5.

I hope this helps you understand how to do these problems on your own.

Answer 3

root(4x+12) -4=0
root(4x+12) = 4
4x+12 = 16
4x =4
x=1

x^2+8=17
x^2 = 9
x = +/- 3

simplify root of 50 over root of 2?
= sqrt(50/2) = sqrt(25) = +/- 5

Answer 4

(i) 4x+12-4=0

4x + 8 = 0

Divide both sides by 4: x +2 = 0

Subtract both sides by 2: x = -2

(ii) x^2+8=17

x^2 = 9

x = 3 or -3

Answer 5

sqrt(4x+12)=4
=>4x+12=16 [squaring both sides]
=>4x=16-12=4
or,x=4/4=1 ans

x^2+8=17
or,x^2=17-8=9
or,x=+-3 [square-rooting both sides]

sqrt50/sqrt2
=(sqrt50)(sqrt2)/(sqrt2)(sqrt2)
=sqrt100/2
=10/2
=5

Answer 6

Ummm the second one is:

sqrt (50) / sqrt (2)

= [(+/- 5) sqrt (2)]/ sqrt (2)

= +/- 5