Find the product.
(p + 10q)(p - 10q)
p2 - 20q2
p2 - 100q2
p2 + 20pq - 100q2
p2 - 20pq - 100q2
2007-06-27 12:49:18 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
p2 - 100q2, i know that for a fact
2007-06-27 12:52:46 · answer #1 · answered by sarahbell515 2 · 0⤊ 0⤋
(p+ 10q)(p-10q)= p2 + 20pq - 100p2
multiply the first bracket with the second one.
2007-06-27 19:54:38 · answer #2 · answered by chetansunnypatil 3 · 0⤊ 0⤋
Use the F.O.I.L. technique: multiply the First #s, then the Outer #s, then the Inner #s, then the Last #s. So....
F: p2
O: -10qp
I: +10qp
L: -100q2
Then combine like terms to get p2 -100q2
2007-06-27 19:51:53 · answer #3 · answered by Amanda 6 · 0⤊ 0⤋
Hey, learn this simple step...FOIL
First, Outside, Inside, Last (order of terms to multiply)
the answer is:
p^2-100q^2
the ^ sign means to the power of btw
Good Luck!!
2007-06-27 19:53:05 · answer #4 · answered by Anonymous · 0⤊ 0⤋
the FOIL method is the simplest, first mulitpy the First numbers so its p^2, the the Outer so its -10pq, then the Inner 10pq, and finally the last numbers -100q^2
so the u get p^2 -10qp + 10pq -100q^2
which simplifies to p^2 -100q^2
2007-06-27 19:53:47 · answer #5 · answered by people suck 6 · 0⤊ 0⤋
It's p^2 - 100q^2
2007-06-27 19:52:17 · answer #6 · answered by Anonymous · 0⤊ 0⤋
Haven't you learned about (a+b)(a-b) = a^2 - b^2?
No, I'm not going to give you the answer. The hint above is sufficient.
2007-06-27 19:53:42 · answer #7 · answered by RobRoy 3 · 0⤊ 0⤋
p2 - 100q2
2007-06-27 19:55:25 · answer #8 · answered by titus_meanmac 2 · 0⤊ 0⤋
(p + 10q)(p - 10q) = p^2-100q^2
2007-06-27 19:52:10 · answer #9 · answered by ironduke8159 7 · 0⤊ 0⤋
pxp -px10q+10qxp-10q*10q
p^2 -100q^2
in general
(a+b)(c+d)
axc+axd+bxc+bxd
2007-06-27 19:54:23 · answer #10 · answered by skipper 7 · 0⤊ 0⤋