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If it did would it produce dark light? and explaine dark energy and dark matter,

2007-06-27 11:17:28 · 5 answers · asked by Anonymous in Science & Mathematics Physics

5 answers

The photon could be considered its own antiparticle. Generally and antiparticle differs from its matter counterpart only in the sign of the electric charge. The photon is not matter, so it's a stretch of definition to say it could have an antiparticle.

Very little is known about dark energy and dark matter. Scientists only reluctantly even contemplate their existence.

2007-06-27 19:12:36 · answer #1 · answered by Frank N 7 · 0 0

Anti Photon

2016-11-08 06:01:01 · answer #2 · answered by ? 4 · 0 0

The photon is its own anti-particle.
It is not a particle if matter, but rather a guage particle (a carrier of a force) and doesn't need an anti-particle.

Strictly speaking, a photon is not a particle, or a wave. It is a particle-wave - which is a fancy way of saying that it is a strange combination of both of these things - but not actually either one.

2007-06-27 11:35:55 · answer #3 · answered by farwallronny 6 · 1 0

This Site Might Help You.

RE:
Is there an anti photon particle if nor why not?
If it did would it produce dark light? and explaine dark energy and dark matter,

2015-08-16 14:01:48 · answer #4 · answered by Anonymous · 0 0

Neutral gauge vector bosons are their own antiparticles. Flip a photon's charge and parity, and you get... a photon. Same with the Z0 particle, for instance.

2007-06-27 14:19:01 · answer #5 · answered by ZikZak 6 · 0 0

I looked it up and, apparently, there is such a thing as an anti photon.
The explanation behind it lost me after about two seconds. If you want to read it, check out this link (and good luck):

http://www.spots.ab.ca/~belfroy/lightphysics/antiphotons.html

2007-06-27 12:00:10 · answer #6 · answered by john g 5 · 0 1

No. Notice in the physics trilogy, E = mc2, m = E/c2, and c2 = E/m, that both mass and energy have as their basis of existence the value of c^2. This is important, but we need to find what the value of "c2" is and what it means. In the last equation we meet with this concept as being that of a energy/mass value. It is a part of the energy within a mass (heat energy) that is able to exist totally apart from either mass or energy (electromagnetic). It appears the value of "c" is that of "h" (Plank's constant), which would explain why it cannot be trapped. Electromagnetic energy itself is divisible as is seen where electron pairs are formed of a single high frequency photon. In that the smallest unit of energy (graviton) is the basis of energy and mass, were there an antiparticle it would have to form at this point, and that appears impossible.

2007-06-27 12:00:39 · answer #7 · answered by d_of_haven 2 · 0 1

Anti-photon particle would only exist where there is anti-matter.

2007-06-27 12:26:06 · answer #8 · answered by Frank S 3 · 1 2

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