Adding and Subtracting Fractions?

Question

I can't figure out these 2 problems... thank you to anyone who can help.

/ = Over
^ = to the power of

Find the indicated sums and differences

1.
2k / 4k^2 - 9
+
3 / 4k^2 - 9


and


2.
x-y / x + y
-
y - x / x + y

Answer 1

Question 1
= 2k / (4k² - 9) + 3 / (4k² - 9)
= (2k + 3) / (2k - 3).(2k + 3)
= 1 / (2k - 3)

Question 2
= (x - y) / (x + y) + (x - y) / (x + y)
= 2.(x - y) / (x + y)

Answer 2

1. (2k+3)/(4k^2-9) just add the numerators since the denominators are the same.

Note my use of parenthesis which is an assumption on my part. It is important for your understanding of the problem to know how the grouping goes.

2. (2x-2y)/(x+y) again just work with the numerators.

Answer 3

it's pretty much asking you to simplify

1. since the denominator are common you can re write
(2k+3)/(4k^2-9)
(2k+3)/(2k+3)(2k-3)
1/(2k-3)
2. same as 1
x-y-(y-x)/(x+y)
x-y-y+x/(x+y)
2(x-y)/(x+y)

Answer 4

1. the answer is:2k+3/4k^2-9=2k+3/(2k+3)(2k-3)=1/(2k-3)
2. the answer is: 2(x-y)/(x+y)

Answer 5

(2k+3)/4k^2-9 = (2k+3)/(2k+3)(2k-3) = 1/(2k-3)

-2y / (x+y)