find the equation of the line that passes through the points (3,-2)and(4,-2)?

Answer 1

Since both points have a y coordinate of -2, the line that connects these points must have y=-2, regardless of the value of x. (x can be anything, as long as y is -2)

So the answer is y=-2

I hope this helps.

Answer 2

Using y = mx + b
we first find the slope (delta y)/(delta x) or rise over run.

delta y = -2 - (-2) = -2 + 2 = 0
delta x = 4 - 3 = 1

So m = 0/1 = 0

The y intercept would be -2 since this is a flat horizontal line, so the equation is:

y = -2

Answer 3

Change in Y divided by Change in X.

Change in Y = -2 - (-2) = 0.
Change in X = 4 - 3 = 1.

You could have stopped after finding the change in Y. The slope is ZERO. You've got a horizontal line.

Answer 4

note that the value of y is the same or that the slope is flat so that should tell you something

Let's go through the process anyway

y = mx + b

m = (y1-y1)/(x1-x2) = (-2--2)/(3-4) = 0/(-1) = 0

Therefore y = 0x + b this means for any x, y = b

From the info above, y = -2 which is the equation for the line

Answer 5

similar to before, get the slope of the line, see your other question

and then

y = mx + c

m = slope.