Adjacent antinodes of a standing wave on a string are a distance 15.00 cm apart. A particle at an antinode oscillates in simple harmonic motion with amplitude .8500 cm and period .0750 s. The string lies along the + x - axis and is fixed at x=0.
At time t=0, all points on the string are at their minimum displacement.
Find the displacement of a point on the string as a function of position and time. (in meters) in the form {y(x,t)=}
Find the speed of propagation of a transverse wave in the string. (m/s)
Find the amplitude at a point a distance 3.0 cm to the right of an antinode. (in meters)
thanx in advanced!
2007-06-27
08:05:40
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3 answers
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asked by
jethaz
2
in
Science & Mathematics
➔ Physics
its in the form y(x,t)=Acos(kx-wt)
i can't figuer out what to plug where or how to do it....
2007-06-27
08:22:10 ·
update #1