Write the equation of the line containing (-1,2) and (-3,8)?

Answer 1

slope = (8-2)/(-3+1) = 6/-2 = -3

point slope form =

y-y1 = m(x-x1)

y-8 = -3(x+3)

y-8 = -3x -9
y =-3x -1

Answer 2

Omg learnt that at like seventh grade... possibly paying interest would help and why ought to somebody else do your homework? next to the actuality that each and all the questions are rediculous common. yet purely placed a numer in on your X or Y or regardless of letter and resolve the subject. Then be taught with given factors and you realize the respond.

Answer 3

find the slope or m
m=
delta y
----------
delta x

or

(y,-y)
---------
(x,-x)

m=
(2-8)
-------
(-1+3)

=
-6
----
2

=
-3

plug it into y=mx+b
y=-3x+b

choose between (-1,2) and (-3,8) to plug into equation above
2=-3(-1)+b
simplify
2=3+b
subtract 3 from both sides
b=-1

plug into equation
y=-3x-1

Answer 4

Starting with y=mx+b and substituting points get

2=m*(-1) + b
8=m*(-3) + b

Two equations with two unknowns.
Solve for m and b and get b= -1 and m= -3

Answer is y= -3x -1

Answer 5

slope is change in y over change in x.
change in y is 8 - 2 = 6
change in x is -3 - -1 = -2
so slope is -3

y = -3x + b
plug in a point:
2 = -3(-1) + b
2 = 3 + b
b = -1

so y = -3x - 1

Answer 6

y=-3x-1