The profits of a company are found by subtracting the companys costs from its revenue. If a companys cost can be modeled by 14x+120,000and its revenue can be modeled by 40x-0.0002x^2, what is an expression for the profit?
2007-06-27 06:14:32 · 8 answers · asked by Berry A 2 in Science & Mathematics ➔ Mathematics
P = R - C
P = 40x - 0.0002x^2 - (14x + 120000)
P = 40x - 14x - 0.0002x^2 - 120000
P = 26x - 0.0002x^2 - 120000
2007-06-27 06:18:20 · answer #1 · answered by yeeeehaw 5 · 0⤊ 0⤋
Let TC and TR be total cost and total revenue respectively
TP = TR - TC = 40x - 0.0002x^2 - (14x + 120000)
TP = 40x - 14x - 0.0002x^2 -120000
TP = 26x -0.0002x^2 - 120000
2007-06-27 13:27:45 · answer #2 · answered by Alfred G 1 · 0⤊ 0⤋
Since profit is revenue minus cost, this can be modeled my simplfying:
(40x - 0.0002x^2) - (14x + 120000) =
40x - 0.0002x^2 - 14x - 120000 =
-0.0002x^2 + 26x - 120000
2007-06-27 13:23:11 · answer #3 · answered by kousuke51 2 · 0⤊ 0⤋
If you are just looking for the profit equation:
Profit=(40x-0.0002x^2)-(14x+120,000)
2007-06-27 13:25:52 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Just Subtract!
40x - .0002x^2 - 14x - 120000
.0002x^2 - 26x - 120000
you could divide each coefficient by .0002 to get a better looking result too.
2007-06-27 13:19:12 · answer #5 · answered by Steph K 3 · 0⤊ 0⤋
Simply subtract the two modeling equations. The result will be a quadratic equation.
2007-06-27 13:20:14 · answer #6 · answered by raf67ab 2 · 0⤊ 0⤋
0.0002x^2-(14x+120,000)
2007-06-27 13:28:04 · answer #7 · answered by Anonymous · 0⤊ 0⤋
Sorry, I'm just in algebra I
2007-06-27 13:18:19 · answer #8 · answered by Anonymous · 1⤊ 1⤋