Factor by grouping 18x^3-21x^2+30x-35?

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2007-06-27 05:31:02 · 4 answers · asked by bee 1 in Science & Mathematics ➔ Mathematics

(18x^3 + 30x) - (21x^2 + 35)

6x * (3x^2 + 5) - 7 (3x^2 + 5)

(6x - 7) (3x^2 + 5)

2007-06-27 05:34:46 · answer #1 · answered by TychaBrahe 7 · 0⤊ 0⤋

18x^3 - 21x^2 + 30x - 35
(18x^3 - 21x^2) + (30x - 35)
3x^2 (6x - 7) + 5 (6x - 7)
(3x^2 + 5)(6x - 7) <== answer

2007-06-27 12:34:52 · answer #2 · answered by C-Wryte 3 · 0⤊ 0⤋

18x^3-21x^2+30x-35
(18x^3+30x) - (21x^2-35)
6x(3x^2+5) - 7(3x^2 + 5)
(6x - 7)(3x^2+5)

2007-06-27 12:43:39 · answer #3 · answered by Amy 2 · 0⤊ 0⤋

(18x^3-21x^2) + (30x-35)

3x^2(6x-7) + 5(6x-7)

(3x^2 + 5) (6x-7)

2007-06-27 12:35:50 · answer #4 · answered by JJ 4 · 0⤊ 0⤋