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solve for x in ln(x) = -1

2007-06-27 05:30:17 · 7 answers · asked by raleighzia 1 in Science & Mathematics Mathematics

7 answers

x = e^-1

x = 1/e

2007-06-27 05:32:32 · answer #1 · answered by TychaBrahe 7 · 1 0

Oh, don't get rid, the ln function is one of the most important, has applications in many areas Just solve it.

Just note ln means log in basis e. The inverse of the base has always log -1. So, ln(x) = -1 implies x =1/e.

2007-06-27 12:36:35 · answer #2 · answered by Steiner 7 · 0 0

The log of a number to a given base is the power to which the base must be raised to give the number.

In this case:-
ln x = - 1
Number is x
Base is e
Power is (- 1)

x = e^(-1)
x = 0.368

2007-07-01 05:31:15 · answer #3 · answered by Como 7 · 0 0

alll you do is subtract the cintermeter and the inch like for a example a cemiter goes to 20 and a inch goes to15 you divide 0 from 15 you no it is 0 so add 1to 20 then divide it by 0

2007-06-27 12:40:11 · answer #4 · answered by Anonymous · 0 1

e^x is the inverse of ln(x), so e^[ln(x)] = x.

Doing the same thing to the other side of the equation:

x = e^(-1);
x=1/x

2007-06-27 12:35:17 · answer #5 · answered by Bob G 6 · 0 0

e^ln(x)=e^-1
x=e^-1

2007-06-27 12:35:37 · answer #6 · answered by pccool52 2 · 0 0

well In(x)=-1
x=e^-1

2007-06-27 12:34:58 · answer #7 · answered by Amy 2 · 0 0

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