2007-06-27 05:13:12 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Using the FOIL method to multiply,
(x-1)(x+m)= x^2 +mx -1x -m
So, since (x-1)(x+m)= x^2+ kx - m , we also know that
x^2+ kx - m = x^2 +mx -1x -m
kx = mx - 1x
kx = (m-1)x
k = m-1
I hope this helps!
2007-06-27 05:21:41 · answer #1 · answered by math guy 6 · 0⤊ 0⤋
k=m-1
2007-06-27 05:15:56 · answer #2 · answered by WD 2 · 1⤊ 0⤋
m-1
2007-06-27 05:17:40 · answer #3 · answered by miggitymaggz 5 · 0⤊ 1⤋
(x-1)(x+m)=x sq.+kx-m
x^2 + xm -x - m = x^2 + kx - m
So k = m - 1
2007-06-27 05:25:38 · answer #4 · answered by Swamy 7 · 0⤊ 0⤋
x^2+mx-x-m=x^2+kx-m
mx-x-kx=0
mx-x=kx
x(m-1)=kx
x canxels on bopth side
k=m-1
2007-06-27 05:17:57 · answer #5 · answered by yuv 1 · 1⤊ 0⤋
Expand left side, (x-1)(x+m)= xsq. +mx -x -m
so xsq. +mx -x -m = xsq. +kx -m
Subtracting xsq. from both sides yields
mx -x -m =kx - m
Adding +m to both sides yields mx - x = kx
K therefore = mx - x
---------
x , x(m - 1)/x, =m-1
There it is: k=m-1
Good luck!
2007-06-27 05:29:08 · answer #6 · answered by Grampedo 7 · 0⤊ 0⤋
xm-x =kx
k= m-1
2007-06-27 05:17:38 · answer #7 · answered by R0ty 1 · 0⤊ 0⤋