Okay so I have (4z - 3)
The next step it asks:
What numerical value must Z be greater than for such a square to exist?
If you know the answer it would help me alot... thanks
2007-06-27 04:57:47 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
4z-3≥0
4z≥3
z≥3/4
2007-06-27 05:21:19 · answer #1 · answered by ђermiona 6 · 1⤊ 0⤋
z should be greater than 0.75
If you substitute 0.75 to z, you get 0, and you cannot get the square root of zero
If you substitute 0.74 to z, you get -0.4, and you can never get the square root of a negative number
However, if you substitute 0.76 to z, you get 0.4, and you can get the square root of any real number greater than 0. In this case, it's 0.2
Thus, Z>0 for such a square to exist
2007-06-27 12:10:43 · answer #2 · answered by dendroidsoldier15 2 · 0⤊ 0⤋
Z must be greater than .75 for a 'square root' to exist.
2007-06-27 12:02:21 · answer #3 · answered by G B 1 · 0⤊ 0⤋
z > 3/4.
Otherwise the the side of the square would be 0 or negative.
2007-06-27 12:02:59 · answer #4 · answered by ironduke8159 7 · 0⤊ 0⤋