simplify the radical expression
2007-06-27 04:52:10 · 13 answers · asked by Jerry S 1 in Science & Mathematics ➔ Mathematics
let (sqrt3)=t
therefore,
(t+5)(t-3)
= t^2 + 2t - 15
= 2(sqrt3)-12
= 2( (sqrt3) - 6)
2007-06-27 04:55:46 · answer #1 · answered by raja 2 · 0⤊ 2⤋
Surds - foil method
F - sqrt3 x sqrt 3 = 3
O - sqrt3 x -3 = -3(sqrt3)
I - sqrt 3 x 5 = 5(sqrt 3)
L - 5 x -3 = -15
3 + 2(sqrt 3) - 15 =
2(sqrt 3) - 12
2007-06-27 11:57:35 · answer #2 · answered by don't stop the music ♪ 6 · 0⤊ 0⤋
sqrt3^2-3 sqrt3+5 sqrt3-15
sqrt3^2-sqrt3(3+5)-15
sqrt3^2-8 sqrt3-15
-12-8 sqrt3
2007-06-27 11:58:27 · answer #3 · answered by yuv 1 · 0⤊ 0⤋
((sqrt3)+5)((sqrt3)-3)
(sqrt3)(sqrt3) - 3(sqrt3) + 5(sqrt3) - 15
3 - 2(sqrt3) -15
-2(sqrt3) - 12
-2(sqrt3 + 6)
2007-06-27 11:57:59 · answer #4 · answered by drea 2 · 0⤊ 0⤋
((sqrt3)+5)((sqrt3)-3)
= 3 -3sqrt(3) +5sqrt(3) - 15
= -12 +2sqrt(3)
2007-06-27 11:57:26 · answer #5 · answered by ironduke8159 7 · 0⤊ 0⤋
No one who got an integer is correct.
Part fo your answer will be 2*sqrt3 and that is not an integer.
2007-06-27 12:02:53 · answer #6 · answered by soelo 5 · 0⤊ 0⤋
((sqrt3)+5)((sqrt3)-3)=
(sqrt(3)^2 + 5sqrt(3)-3sqrt(3)-15)=
3-15 + (5-3)sqrt(3)=
-12+2sqrt(3)
2007-06-27 12:02:16 · answer #7 · answered by seed of eternity 6 · 0⤊ 0⤋
3+(2*(sqrt3))-15
2007-06-27 11:56:48 · answer #8 · answered by star_prince0 2 · 0⤊ 1⤋
Hi,
((sq rt3)+5)((sq rt3)-3) =
(â(3)+5)(â(3)-3)
FOIL these together:
â9 -3â(3) + 5 â(3) - 15
Simplify the 1st radical and combine like terms.
3 -3â(3) + 5 â(3) - 15 =
-12 + 2â(3) <== answer
I hope that helps!! :-)
2007-06-27 11:57:07 · answer #9 · answered by Pi R Squared 7 · 0⤊ 0⤋
Apply FOIL
Sqrt(3^2) -3sqrt (3) + 5sqrt (3) -15
3 + 2sqrt(3) -15
-12 + 2sqrt(3)
2007-06-27 11:56:24 · answer #10 · answered by gfulton57 4 · 0⤊ 0⤋