what is the equation of the linear function that passes through (6,-4) and is parallel to line 4x-2y=4?

Answer 1

4x - 2y = 4
-2y = -4x + 4
y = 2x - 2

Slope of given line is 2

Slope of a line parallel is also 2.

So, using point-slope form:
y - y1 = m(x - x1)
y - (-4) = 2(x - 6)
y + 4 = 2x - 12
y = 2x - 16

Or, in standard form: 2x - y = 16

Answer 2

First, rearranging the equation the problem gave you to say “y = “ will help you visualize the line a little better. After doing this, the equation reads “y = 2x – 2.” This is a line of slope of 2, and a y intercept of -2.

Any line parallel to this first line needs the same slope (otherwise it’s not parallel!). So we know that the answer must be something like “y = 2x + b” but finding “b” is where you’re probably getting hung up.

The additional information provided will help you do this. You know that the answer passes thru the point (x = 6, y = -4). Plug this point into “y = 2x + b” and then solve for “b”.

You now have all the info you need to complete your answer.

Answer 3

first find slope

4x-2y = 4
add 2y to both sides
4x=2y+4
subtract 4 from both sides
4x-4=2y
divide all by 2
2x-2=y
y=2x-2
this is in y=mx+b form with m being the slope and b being the y intercept

the slope of your new line is 2
y = m*x + b and you know from the point
x = 6
y = -4
m = 2
so solve for b
-4 = 2*6 + b
-4 = 12 + b
subtract 12 from both sides
b = -16

so the
m = slope = 2
and the b = y intercept = -16

your line is
y = 2x - 16

Answer 4

Given: 4x-2y=4 (6,-4)

Solution:
m(sub)1 = 2 ==>slope of the equation
m(sub)2 = 2 ==>slope of the parallel equation

y-y(sub)1 = m (x-x(sub)1)
y-(-4) = 2(x-6)
y+4 = 2x-12
y = 2x-16 or 2x-y = 16

Answer 5

hi
when two equations are parallel, they must have the same gradient, therefore
4x-2y=4
2y=4x-4
y=2x-2 , the gradient of this line is 2 since (y=mx+c)
now, to find the equation of the straight line at (6,-4) , use the formula:
y - y1 = m(x-x1)
y - (-4) = 2(x-6)
y = 2x - 12 -4
therefore the equation is:
y = 2x - 16

Answer 6

Slope (m) of 4x-2y=4 is 2

Equation of a line = y - y1 = m ( x - x1 )

(x1=6)(y1=-4)(m=2)

y - (-4) = 2 ( x - 6)
y + 4 = 2x - 12
-2x + y = -12 - 4
-2x + y = -16
2x - y = 16

Hope this helps!!!

Answer 7

1) 4x-2y=4 ===> -2y=4-4x ===> y=2x-2

2) equation is
(y+4)=2(x-6)
y = 2x-8

Answer 8

Three steps:
Put given eqtn in slope-intercept form (y=mx+b)
m is intercept of parallel line
Solve for b, given (6,-4) as a solution for parallel line
1. 2x-1=y
2. Parallel line has slope of 2: y= 2x+b
3. Sub data: -4=12+b => b = -16

Answer 9

eqn of the other parallel line will be of the form,
4x - 2y = k
sub (6,-4) in this, we have k=32
so the eqn is 4x - 2y = 32 i.e 2x - y =8.

Answer 10

a line parallel to 4x-2y=4is
4x-2y=a
if it passes through (6,-4).
then
24+8=a, a=32
the reqd. eq uation is 4x-2y=32.