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just imagine a water column. the bottom part of the column will experience pressure due to the water above..when pressure increases volume decreases..so when volume decreases the density should increase...which means that water at the bottom have a higher density than the water above it....is this right?? pls give the sources of your answer also...

2007-06-27 02:41:42 · 5 answers · asked by jr 2 in Science & Mathematics Physics

5 answers

This is true. However, in classical mechanics, we typically treat fluids as 'incompressible,' which basically means that we ignore this increase in density when subjecting the system to analysis. However, it is relatively easy to solve a fluid system when taking this into account too, but one must consider the non-uniform viscosity of the column, and that turbulent effects become depth-dependent.

2007-06-27 02:46:40 · answer #1 · answered by Not Eddie Money 3 · 0 0

Look at a pressure/volume (PV) diagram for water. This is available anywhere online with PV diagram water keyword search. The density change with pressure is muy tiny, hence the incompressible assumption.

2007-06-27 10:40:42 · answer #2 · answered by Shawn A 3 · 0 0

It is theoretically right. Although, given that liquids are mostly incompressible, the density differenece between the top and the bottom of the column might be negligible.

2007-06-27 09:48:26 · answer #3 · answered by Israfel 3 · 1 0

Here's your source. I assume you know how to convert pressure to depth, given density.

2007-06-27 22:53:09 · answer #4 · answered by Dr. R 7 · 0 0

Density remains constant, pressure increases.

2007-06-30 12:48:22 · answer #5 · answered by johnandeileen2000 7 · 0 0

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