y=(2x-3)/(3x+5) solve for x?

Question

please show work

unfortunately, it is possible to solve, there is an answer

Answer 1

2x-3 = y(3x+5)
2x-3 = 3xy+5y
2x-3xy = 5y+3
x(2-3y) = 5y+3
x = (5y+3)/(2-3y)

C-Wryte's answer can be simplified to what I got by factoring our -1 from the numerator and denominator.

Answer 2

The first answerer is correct, unless you just want to solve for x in terms of y, which could be done:

y = (2x - 3) / (3x + 5)
==> multiply by (3x + 5) on both sides
y*(3x + 5) = 2x - 3
==> distribute:
3xy + 5y = 2x - 3
==> subtract 5y from both sides
3xy = 2x - 5y - 3
==> subtract 2x from both sides
3xy - 2x = -5y - 3
==> factor out an x on the left side
x*(3y - 2) = -5y - 3
==> divide by (3y - 2)
x = (-5y - 3) / (3y - 2)

Your answer is: x = (-5y - 3) / (3y - 2)

Answer 3

Multiply both sides by (3x +5):

y (3x + 5) = 2x -3

then distribute "y" :

3yx + 5y = 2x - 3

then gather terms that have "x" to one side:

3yx -2x = -5y - 3

Factor out x from terms on the left:

(3y -2) x = -5y -3

Then divide both sides by (3y -2)

x = (-5y -3)/(3y -2)

(If you want, multiply the numerator and denominator of the term on the right side by -1

x = (5y +3)/(2 - 3y)

just to look a bit tidier.)

Answer 4

2x-3 = y(3x+5)
2x-3 = 3xy+5y
-5y-3 = 3xy -2x
-5y-3 = x(3y-2)
x = -(5y+3)/(3y-2)
x= (5y+3)/(2-3y)

Answer 5

The equation is impossible to solve. The value of y is needed if we wants to solve for x.

The question should in fact be changing the subject of x and not solving the equation.

Answer 6

y=(2x-3)/(3x+5)
y(3x+5)=(2x-3)
3xy+5y=2x-3
3xy-2x=-(5y+3)
x(3y-2)=-(5y+3)
x=-(5y+3)/(3y-2)