Math problems?

Question

Ramon has a horse and a carabao.The horse is 2/3 as old as the carabao.The difference between thier ages is 4 years.How old is the carabao?

Answer 1

Let x be the age of the carabao.
Let y be the age of the horse.

We are given the following information:
y = (2/3)x
x - y = 4

Plugging in the y-value from the first equation into the second:
x - (2/3)x = 4
(1/3)x = 4
Then triple both sides of the equation to get:
x = 12

The carabao is 12 years old.

Answer 2

Carabao is older than horse as the horse is 2/3 of him.

Equatin (1) ==> Carabao - Horse = 4

And

Equation (2) ==> Horse = 2/3 Carabao;

if we write instesd of horse 2/3 Carabao in equation (1)

Carabao - 2/3 Carabao = 4

So Carabao is 12 and Horse is 8

Answer 3

1/3 of difference = 4 years.

4 x 3 = 12.

Answer 4

Try drawing out the model.
Horse 2 units
Carabao 3 units

The difference is 1 unit = 4 year old

Carabao 3 units = 3 x 4 = 12 year old.

Answer 5

12

Answer 6

Because their age difference is 4 years, you can assume the 2/3 will be a multiple of four. The first one of this is 8/12. That means that the horse is 8 and the caribou is 12. This is four years difference at 2/3s.

Hope it helps!

Answer 7

Answers with Solutions

Qns. 1:

Horse = 2/3n
Carabao = n

n - 2/3n = 1/3n

1/3n = 4
n = 12

Therefore, Carabao is 12 years old.

Hope This Solutions Will Help In Answering Your Questions ;)

G0n9 G0n9™
Mathematician

Answer 8

let age of carabao be --- x
then age of horse is ---- 2/3*x
difference us 4
x -2/3*x-=4
x/3=4
x=12
carabao is 12 yrs old