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I don't know if I am using the right terminology, but I would like to know how much pure energy is contained in the average human? And there are 2 sub questions.
Consider that a person weighing 150 pounds is exploded in a nuclear reaction somehow, as if the person were a nuclear bomb. How large a blast would you get?
Would we simply use Einsteins formula e=mc squared?
Or if we considered the energy released slowly like in a nuclear power plant, how much electricity would be produced by burning all the nuclear material in the average human?
I hope I have asked this in a way that makes sense.

2007-06-26 18:39:43 · 2 answers · asked by Phil H 2 in Science & Mathematics Physics

2 answers

assuming you could explode your human
into pure nuclear energy with no loss
you would use E=mc^2
if m is in kg and c=300000000 m/s
then E will be in joules
150lb = 150/2.2 kg=68.2 kg
so E = 68.2 * 300000000^2
=6138000000000000000 joules in a 150lb human
=6.1billion billion joules
= 1700000000000 kw.hr
the average home uses about 2900kw.hr per year so
1 human would power
1700000000000/2900 =590 million homes for a year

the end
.

2007-06-26 22:13:32 · answer #1 · answered by The Wolf 6 · 0 0

Well, you realise it's a creepy question. But - fine, I'll answer. You can't really explode a human body the same way you explode a nuclear bomb. It just doesn't work that way - you don't have much of radioactive material inside of you unless you were eating something terribly wrong, like nuclear waste. All the energy that's there is pretty much similar to what you find in food. Can we think about a cow instead, from this point on? A very small 150 pounds cow? The answer is on the order of 30000 kilocalories.

2007-06-26 21:43:36 · answer #2 · answered by Snowflake 7 · 0 0

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