Give the equation of the line that contains (-6,-3) and (-4,-3)?

Question

can someone please explain the steps to solving it.

Answer 1

The equation of a line is y = mx + b, where m is the slope of the line, x and y are points on the line, and b is where it crosses the y-axises.

First, you should find the slope, it is rise over run, or the difference in the y values of the two points, divided by the difference in the x values of the two points.

m = ((-3) - (-3)) / ((-6) - (-4))
m = ((-3) + 3) / ((-6) + 4)
m = (0) / (-2)
m = 0

Because the slope is zero, it is a horizontal line. now to find b, you can re-arange the equation y = mx + b, so b is on a side by it's self; b = y - mx, then you plug in the value for m, and pick one of the points you know are on the line, and place the x value in for x, and the y value in for y.
b = y - mx
b = y - (0)x
b = (-3) - (0)(-6)
b = -3 - 0
b = -3

So, the equation of the line, in slope-intercept form is y = -3 (actually y = (0)x + (-3), but it simplifies to y = -3), which means that it is a horizontal line crossing the y axises at -3, it has a domain of x = all real numbers, and a range of y = -3

y = (0)x + (-3)
y = -3

Answer 2

The equation for a line is y = mx + b, where m is the slope and b is the y-intercept. Find the slope first:

m = change in y's / change in x's.
m = [-3 - (-3)] / [-4 - (-6)]
m = 0 / 2
m = 0

So the slope of the line is 0. That means you have a horizontal line, because the line neither rises nor falls as it moves from left to right.

To find the y-intercept, ordinarily you would plug one of the x values into the equation and solve for b. However, because the slope is 0, it will make no difference what number is plugged in for x, the slope will make the x term drop out of the equation entirely. You can still, however, plug a y value into the equation. Since the y value for each point is the same, you are left with this:

y = 0 - 3
y = -3

This is exactly what you would expect since the graph is a horizontal line.

Answer 3

first you have to find the slope which is like (y1-y2),(x1-x2). once you get that you have to plug it into the equation of the line or y=mx+b where m is the slope. use one of the ordered pairs for y and x and the slope for m and then solve for b, or the y intercept. thennn put in the slope and the y intercept at the end and then you have the equation of the line

Answer 4

you can find the slope of the line using the formla slope (m) = (y1-y2) / (x1-x2)

so m = (-3 + 3) / (-6 + 4) = 0

after you find the slope, you use the point slope equation: y-y1 = m (x-x1) to get the equation of the line

y +3 = 0 (x+6)
y = -3