ok. so the summ of three consecutive even numbers is 48. What are the smallest of these numbers???
2007-06-26 12:08:27 · 5 answers · asked by (lo.RUH) 2 in Education & Reference ➔ Homework Help
Let a, a + 2 and a + 4 be the three numbers. So,
a + a + 2 + a + 4 = 48
3a = 48 - 6 = 42
So, a = 42/3 = 14
The smallest of the three numbers is a = 14
Easy, isn't it?
We could have done this another way too:
Since sum is 48, average will be 16. Since they are consecutive even numbers, 16 is the middle one and 14 and 18 are the others. So, 14 is the smallest number.
2007-06-26 12:12:05 · answer #1 · answered by Swamy 7 · 0⤊ 0⤋
14
2007-06-26 12:18:31 · answer #2 · answered by mathvideosonline.com 2 · 0⤊ 0⤋
the numbers are 14, 16, & 18 so the smallest is 14 =]
2007-06-26 12:35:03 · answer #3 · answered by Anonymous · 0⤊ 0⤋
x+x+x=48
3x=48
x=16
14+16+18=48
smallest number is 14
2007-06-26 12:13:31 · answer #4 · answered by clayh3 2 · 1⤊ 1⤋
14,16,18 (14)
2007-06-26 12:45:55 · answer #5 · answered by Anonymous · 0⤊ 0⤋