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Abductin is an elastic protein found in scallops, with a Young's modulus of 4.0 106 N/m2. It is used as an inner hinge ligament, with a cross-sectional area of 0.73 mm2 and a relaxed length of 1.1 mm. When the muscles in the shell relax, the shell opens. This increases efficiency as the muscles do not need to exert any force to open the shell, only to close it. If the muscles must exert a force of 1.7 N to keep the shell closed, by how much is the abductin ligament compressed?

2007-06-26 11:35:27 · 3 answers · asked by salvnjc4ever 1 in Science & Mathematics Physics

3 answers

nothing more to add

2007-06-30 08:18:23 · answer #1 · answered by Abhinesh 4 · 0 1

An interesting application of Young's modulus E, since most problems assume stretching under tension. The stress is 1.7 N / 0.73 mm^2 = 2328767 N/m^2.
strain deltaL / L = stress / E = 0.5822
compression distance deltaL = 1.1 * strain = 0.6404 mm
Note that the assumption of a linear stress-strain relationship implicit in this calculation is actually not valid for large strains, especially in compression (e.g., what happens when you compress something 100%?). See the ref. for discusion of this.

2007-06-29 11:10:43 · answer #2 · answered by kirchwey 7 · 1 0

The preliminary power interior the gadget equals the artwork accomplished to bypass the spring from equilibrium. this could be one million/2*ok*x^2 (the two combine or draw a stress vs distance diagram to make certain this), observe you're able to use commonplace contraptions so the area is 0.16m. After 2 oscillations the amplitude is decreased to 0.sixteen*0.seventy 5*0.seventy 5. artwork out the ability final utilising the comparable formulation as above. the variation between the two figures is the quantity of power lost. because of the fact we are understanding power on the extremes of the oscillation we don't could rigidity approximately kinetic power, each and all of the ability is skill power of the spring.

2016-10-03 04:47:25 · answer #3 · answered by ? 4 · 0 0

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