Hey there!
I don't know, whether x-2 is being raised or x being raised, but I'll solve for both ways.
250e^x-2=3000 -->
250e^x=3002 -->
e^x=3002/250 -->
e^x=12.008 -->
ln e^x=ln 12.008 -->
x ln e = ln 12.008 -->
x (1) = ln 12.008 -->
x= ln 12.008 -->
x=2.49 (rounded to two decimal places)
Now, I'll solve it, when x-2 is raised to a power.
250e^x-2=3000 -->
e^x-2=12 -->
ln e^x-2=ln 12 -->
x-2 ln e=ln 12 -->
x-2 (1)=ln 12 -->
x-2=ln 12 -->
x=2+ln 12 -->
x= 4.49 (rounded to 2 decimal places)
So the value of x is either 2.49 or 4.49.
I hope it helps!
2007-06-26 11:34:53
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answer #1
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answered by ? 6
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250e^x-2 = 3000
e^x-2 = 3000/250
e^x-2 = 12
ln(e^x-2) = ln(12)
x-2 = ln(12)
x = ln(12) + 2
x = 4.485
2007-06-26 18:17:59
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answer #2
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answered by drea 2
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250 e^x = 3000 +2 = 3002
e^x = 3002/250 =12.008
x lin e = ln 12.008
x = ln 12.008 = 2.4855
2007-06-26 18:16:49
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answer #3
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answered by CPUcate 6
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I think CPUcate is correct. If you divide by 250 first you also have to divide the 2 by 250.
2007-06-26 18:22:44
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answer #4
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answered by Al Phanti 2
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is it
250 e^(x-2) = 3000
e^(x-2) = 12
x-2 = ln 12
x = 2 + ln 12
x = 4.4849
or is it what cpucate did?
2007-06-26 18:20:20
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answer #5
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answered by Philo 7
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X = ebonidimplz
2007-06-26 18:15:41
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answer #6
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answered by coolguy 3
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Why?
2007-06-26 18:19:22
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answer #7
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answered by kevrigger 5
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2⤋