solve for b1 given the area of a trapezoid is as follows: a=h(b1+b2)/2
2007-06-26 09:36:16 · 6 answers · asked by shirandjoy 2 in Science & Mathematics ➔ Mathematics
AREA OF TRAPEZOID
A= 1/2(b1 +b2) * h where b1 and b2 are the two paralell sides and h is the height.
The objective is to make b1 the subject by transposing.
A = 1/2(b1 +b2)*h multiply by 2 to get the following
2A = (b1 + b2)*h use the distributive property and multiply by h to get
2A = b1h +b2h Divide by h and subtract b2 to get
b1= (2A/h)-b2
Your answer is correct. Good job!
2007-06-26 09:44:48 · answer #1 · answered by maple37 1 · 0⤊ 0⤋
Area 96,height 8 what is the base
2016-03-16 08:16:50 · answer #2 · answered by tralisa w 1 · 0⤊ 0⤋
Yes, absolutely.
a=h(b1+b2)/2
2a/h = b1 + b2
2a/h - b2 = b1
2007-06-26 09:40:20 · answer #3 · answered by Timothy H 4 · 0⤊ 0⤋
Yes
2007-06-26 09:40:23 · answer #4 · answered by ironduke8159 7 · 0⤊ 0⤋
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2016-12-08 19:26:40 · answer #5 · answered by Anonymous · 0⤊ 0⤋
that's what i got
2007-06-26 09:41:02 · answer #6 · answered by imajesuslover21 2 · 0⤊ 0⤋