4(2z - 3) = 7(z + 5)
2007-06-26 08:46:28 · 12 answers · asked by casper5 3 in Science & Mathematics ➔ Mathematics
4(2z - 3) = 7(z + 5)
8z - 12 = 7z + 35
8z - 7z = 35 + 12
z = 47
2007-06-26 08:49:11 · answer #1 · answered by fofo m 3 · 1⤊ 0⤋
1. Distribute 4 to (2z-3) and 7 to (z+5)
8z-12=7z+35
2. Whatever you do to one side of the equation you have to do to the other side.
Subtract 7z from both sides
z-12=35
3. Add 12 to both sides
z=47
Your answer is z=47
2007-06-26 15:59:15 · answer #2 · answered by Anonymous · 0⤊ 0⤋
4(2z - 3) = 7(z + 5)
8z - 12 = 7z + 35
8z - 7z = 35 + 12
z = 47
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2007-06-26 16:06:31 · answer #3 · answered by aeiou 7 · 0⤊ 0⤋
4(2z - 3) = 7(z + 5)
8z - 12 = 7z + 35
8z - 12 - 7z = 7z + 35 - 7z
z - 12 = 35
z - 12 + 12 = 35 + 12
z = 47
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Check
4(2z - 3) = 7(x + 5)
4[2(47) - 3] = 7(47 + 5)
4[94 - 3] = 7(52)
4[91] = 364
364 = 364
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2007-06-26 15:59:14 · answer #4 · answered by SAMUEL D 7 · 0⤊ 0⤋
4(2z - 3) = 7(z + 5)
8z - 12 = 7z + 35
8z - 7z = 12 + 35
z = 47
2007-06-26 15:56:08 · answer #5 · answered by kdb110493 1 · 0⤊ 0⤋
4(2z - 3) = 7(z + 5)
1st multiply 4 through (2z-3) and multiply 7 through (z=5) :
8z -12 = 7z + 35
Now put all the z's on one side and all the numerals on the other:
8z - 7z = 35 + 12
z = 47
2007-06-26 15:53:15 · answer #6 · answered by Alisa 1 · 0⤊ 0⤋
first you use the distributive property to make
4 times 2z -4 times 3 =7 times z + 7 times 5
equals
8z-12=7z+35
add 12 to both sides and subtract 7z from both to get
1z=47
2007-06-26 15:56:19 · answer #7 · answered by in37touch 1 · 0⤊ 0⤋
to solve
4(2z-3)=7(z+5)
Multiply Through
8z-12 = 7z+35
Then get unknown to one side by adding 12 to both sides and subtracting 7z from both sides
z=47
2007-06-26 15:55:52 · answer #8 · answered by Cassie 2 · 0⤊ 0⤋
4(2z-3)=7(z+5)
8z-12=7z+35
z-12=35
z=47
2007-06-26 15:50:06 · answer #9 · answered by Lauren 5 · 0⤊ 0⤋
8z - 12 = 7z + 35
z = 47
2007-06-26 15:49:05 · answer #10 · answered by miggitymaggz 5 · 0⤊ 0⤋