Solve for x and receive 10 points!! Help!!!!!!?

Question

Solve for x and explain or show work:


x^3 = 4x

Answer 1

x^3 - 4x = 0

x (x^2 - 4) = 0

either x = 0 or x^2 - 4 = 0

if x^2 -4 = 0

x^2 = 4

x = +2 or -2

remember -2 times -2 = +4 and +2 times +2 also = +4

x can be 0, +2, -2

Answer 2

x³ = 4x

Transpose 4x

x³ - 4x = 4x - 4x

x³ - 4x = 0

Common factor x

x(x² - 4) = 0

Inside the parenthesis factor the difference of two squares

x(x - 2)(x + 2) = 0

- - - - - - -

Roots

x = 0

- - - - - - -

Roots

x - 2 = 0

x - 2 + 2 = 0 + 2

x = 2

- - - - - - - -

Roots

x + 2 = 0

x + 2 - 2 = 0 - 2

x = - 2

- - - - - - - - s-

Answer 3

x^3/x = 4

x^2=4

x= -2, 2

Answer 4

yeah i got the same as that one guy
x=0, 2, -2

just put everything on the one side of x
x^3 - 4x=0

factor out x
x(x^2 -4)=0

and factor again
x(x-2)(x+2)=0
then set each to zero and solve for x

Answer 5

x^3=4x

(x^3)/x=4

x^2=4

x=square root of 4

x = 2 or -2

Answer 6

x^3=4x, divide by x

(x^3)/x=4, simplify the left side

x^2=4, square root of both sides

x=sqrt 4 or x=+/-2

Answer 7

x^3 - 4x = 0

x(x^2-4) = 0

Use the difference of squares rule:

x(x+2)(x-2) = 0

x = 0 or -2 or 2

Answer 8

First we note the trivial solution x = 0.

Then we can simplify by dividing both sides by x:

x^2 = 4

From this it's clear that x = 2 or -2.

So the solutions are 0, 2, -2.

Answer 9

x^3 = 4x

(x^3)/x = 4

(x^3)/(x^1) = 4

x^(3-1) = 4

x^2 = 4

sqrt (x^2) = sqrt (4)

x = -2, 2

Answer 10

to discover the y-intercept, you're able to set x to 0 interior the equation: 3(0) - 4y = -12 or -4y = -12. you're able to then divide the two facets by way of -4 to get the variable y by way of itself: y = -12 / -4 because of the fact the numbers are the two damaging, the respond would be a good variety. (12/4) = 3. So the y-intercept is 3.