HELP please with this question!!?

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Evaluate: log2[1/(2^3)]

Note: 2 is the base, and [1/(2^3)] is x.

2007-06-26 08:15:16 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

log base 2 (2^-1/3) = -1/3

2007-06-26 08:21:39 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋

-2

2007-06-26 15:22:00 · answer #2 · answered by Anonymous · 0⤊ 0⤋

-3

{1/(2^3} = 1/8

switch it out of Log in to exponents
so 2^x=1/8

with negetive exponents you put (1/the number from the exponent)

2007-06-26 15:25:58 · answer #3 · answered by stuartah2000 2 · 0⤊ 0⤋

hint: 2^(-3)=1/(2^3)

2007-06-26 15:22:24 · answer #4 · answered by Theta40 7 · 0⤊ 0⤋