solve EACH EQUATION PLEASE HELEP ME!!
DIRECT VARIATION AND PROPORTION!
2007-06-26 07:46:45 · 5 answers · asked by king 1 in Science & Mathematics ➔ Mathematics
1) 27 = c(-4)
c = -27/4
2)-8= -3/4z
z = -8 * -4/3
z = 32/3
(3.) k/4= -20
k = -20 *4
k= -80
(4.) n/2=5/8
n = 5/8 *2
n= 5/4
(5.) 2(4y+1)=3y
8y+2 = 3y
5y = -2
y = -2/5
2007-06-26 07:49:58 · answer #1 · answered by sweet n simple 5 · 0⤊ 2⤋
27= C(-4)
C= -27/4
-8 = -3/(4z)
-32z= -3
z = 3/32
k/4 = -20
= 4(-20) = -80
n/2 = 5/8
n= 2*5/8 = 10/8 = 5/4
2(4y+1)=3y
8y +2 = 3y
8y-3y = -2
5y = - 2
y = - 2/5
2007-06-26 15:16:45 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
27=C(-4)
c = -27/4
-- --
-8= -3/4z
z = -8 * -4/3
z = 32/3
--- --
(3.) k/4= -20
k = -20*4
k = -80
-- ---
(4.) n/2=5/8
n = 5/8*2
n = 5/4
-- --
(5.) 2(4y+1)=3y
8y + 2 = 3y
8y - 3y = -2
5y = -2
y = -2/5
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2007-06-26 17:16:08 · answer #3 · answered by aeiou 7 · 0⤊ 1⤋
c=27/-4
c=-6(3/4)
z=8(4/3)
z=32/3
z=10(2/3)
k=-20*4
k=-80
n=5(2)/8
n=5/4
n=1(1/4)
8y+2=3y
8y-3y=-2
5y=-2
y=-(2/5)
2007-06-26 14:58:16 · answer #4 · answered by MAHAANIM07 4 · 0⤊ 2⤋
!) -(27/4)=C
2. z=3/32
-32z=-3
z=3/32
3. k=-80
4. n=5/4
5. 8y+2=3y
5y= -2
y=-2/5
2007-06-26 14:51:09 · answer #5 · answered by yuv 1 · 0⤊ 3⤋