Could someone please help me with this problem?

1 ⤊

If y = ln(x^2)/2, then dy/dx is:

a) 2lnx
b) 2lnx/4
c) 1/x
d) 1/2x^2

2007-06-26 07:31:48 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

y = ln (x^2) /2
= 2 ln x/2
= ln x

So dy/dx = 1/x

2007-06-26 07:36:16 · answer #1 · answered by Madhukar 7 · 1⤊ 0⤋

y = ln(x^2)/2 =2*ln(x)/2 =ln(x) so
dy/dx = 1/x

2007-06-26 07:36:52 · answer #2 · answered by nyphdinmd 7 · 0⤊ 0⤋

ln(x²) = 2 ln x,
so we have to find dy/dx for
y = 2 ln x/2 = ln x.
The answer is c). 1/x.

2007-06-26 07:36:17 · answer #3 · answered by steiner1745 7 · 0⤊ 0⤋