I am working on systems of linear equations and have to solve by using substitution?

Question

my question is this. the problem is 4x -12y = 5 and -x + 3y = -1.

In order to do this i have to switch the problem so its y = or x =. well the second problem x is negative. do i multiply the problem by negative one so that x is positive?

Answer 1

yes u r right
4x -12y = 5..1st

-x + 3y = -1.
now multiply the whole equation by -4
4x -12y = 4......2nd

now solving 1st and 2nd
since 4x-12 = 5 and also equal to 4
these equations r inconsistent and hv no solution

Answer 2

by substitution
x=3y+1
so4(3y+1)-12y=0
and 4=0 wrong No solution

If you multiply the 2nd equation by-4 you get 4x-12y=4
Both equation have the same first side and it is impossible to be = 4 and 5

Answer 3

Eq. #1: 4x - 12y = 5
Eq. #2: -x + 3y = -1

Step #1: Multiply Eq. #2 by -1
Result #1: x - 3y = 1

Step #2: Add 3y to Eq. #2
Result #2: x = 3y + 1

Step #3: Substitute Result #2 into Eq. #1
Result #3: 4(3y + 1) - 12y = 5

Step #4: Simplify Result #3
Result #4: 12y + 4 - 12y = 5

Step #5: Simplify Result #4
Result #5: 4 = 5

Therefore, you can't get an answer for x,y to make both equations works.