i have a question,
is there a quick way of doing
4.497x(10 to the power of 9) - 5.8x(10 to power of 7)??
And give your answer in standard form??
Thanks
2007-06-26 06:59:22 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
You have to place them in the same exponent first.
I would move the decimal two places right and reduce the exponent by two, of the first number:
4.497 x 10^9 = 449.7 x 10^7
449.7 x 10^7 - 5.8 x 10^7 =
(449.7 - 5.8) x 10^7 =
443.9 x 10^7
Then you have to restore the result to standard form:
443.9 x 10^7 =
4.439 x 10^9
2007-06-26 07:03:34 · answer #1 · answered by McFate 7 · 1⤊ 0⤋
The easiest way would be to make the two numbers have the same power of 10:
4.497x(10^9) = 449.7x(10^7)
Subtracting the two, you get:
443.9x(10^7) = 4.439x(10^9) = 4,439,000,000
2007-06-26 07:03:55 · answer #2 · answered by Dave 6 · 0⤊ 0⤋
yes there is dear...
take da powers commone that is...
4.497x(10 to the power of 9) - 5.8x(10 to power of 7)
10 ^7(4.497x10 ^2 - 5.8)
!0^7(44.97-5.8)
10^7(39.17)
2007-06-26 07:05:23 · answer #3 · answered by yuv 1 · 0⤊ 0⤋
Are those exponents? like 6 x 10^6 = 6,000,000
2016-05-21 01:11:19 · answer #4 · answered by ? 3 · 0⤊ 0⤋
put them both so they have the same 10 to the x
so...
4.497x10^9
-0.058x10^9
=
4.439x10^9
Now put it in standard form.
4,439000,000
2007-06-26 07:06:30 · answer #5 · answered by Matia 3 · 0⤊ 0⤋