1.x2-12x+36
2.16b4 -1
3.9a3-12a2+3a
plz help
2007-06-26 05:40:59 · 9 answers · asked by brittney_lovely 1 in Science & Mathematics ➔ Mathematics
x² - 12x + 36 = 0
The middle term is - 12x
Find the sum of the middle term
first term x² = 1
Multiply the first term 1 times the last term 36 equals 36 and factor
Factors of 36
1 x 36
2 x 18
3 x 12
4 x 9
6 x 6. . .←. .use these factors
- 6 and - 6 satisfy the sum of the middle term
insert - 6x and - 6x into the equation
x² - 12x + 36 = 0
x² - 6x - 6x + 36 = 0
x(x - 6) - 6(x - 6) = 0
(x - 6)(x - 6) = 0
- - - - - - - - - - - - -
Difference of two squares
16b² - 1= 0
(4b² - 1)(4b² + 1) = 0
- - - - - - - -s-
2007-06-26 06:51:20 · answer #1 · answered by SAMUEL D 7 · 1⤊ 0⤋
1. x^2 - 12x + 36
Look for factors of 36 whose sum is - 12 and whose product is + 36
-6 and -6 fit the bill
(x - 6)(x - 6)
2. 16b^4 - 1
A difference of two squares
(4b^2 + 1)(4b^2 - 1)
(4b^2 + 1)(2b + 1)(2b - 1)
3. 9a^3 - 12a^2 + 3a
3a(3a^2 - 4a + 1)
3a(3a - 1)(a - 1)
2007-06-26 05:56:24 · answer #2 · answered by Anonymous · 0⤊ 0⤋
1.x^2 -12x+36 =
(x - 6)².
[Difference of squares.]
2.16b^4 -1
(4b² + 1)(4b² - 1) =
(4b² + 1)(2b + 1)(2b - 1).
3.9a3-12a2+3a =
(3a)(3a² - 4a + 1) =
(3a)(3a - 1)(a - 1).
2007-06-26 05:50:07 · answer #3 · answered by Anonymous · 0⤊ 0⤋
(1) (x - 6)(x - 6) = (x - 6)^2
(2) (4b^2 - 1)(4b^2 +1) = (2b - 1)(2b + 1)(4b^2 + 1)
(3) 3a(3a^2 - 4a + 1) = 3a(3a - 1)(a - 1)
2007-06-26 05:45:14 · answer #4 · answered by yeeeehaw 5 · 0⤊ 0⤋
1. (x - 6)(x - 6)
2. (4b² + 1)(4b² - 1) = (4b² + 1)(2b + 1)(2b -1)
3. 3a(3a² - 4a + 1) = 3a(3a - 1)(a - 1)
2007-06-26 05:44:38 · answer #5 · answered by Dave 6 · 0⤊ 0⤋
1) (x-6)(x-6) = (x-6)^2
2) (4b^2-1)(4b^2+1) = ((2b-1)(2b+1)(4b^2+1)
3) 3a(3a^2-4a+1) = (3a)(3a - 1)(a-1)
2007-06-26 05:45:43 · answer #6 · answered by gfulton57 4 · 0⤊ 0⤋
x^4 - 80 one x^4 - 3^4 (x^2)^2 - (3^2)^2 (x^2 - 3^2)(x^2 + 3^2) (x - 3)(x + 3)(x^2 + 3^2) this is the furthest you are able to bypass with out utilizing complicated numbers. in case you prefer to apply complicated numbers: (x - 3)(x + 3)(x^2 - (3i)^2) (x - 3)(x + 3)(x - 3i)(x + 3i) in case you have a sturdy reminiscence, you ought to to endure in innovations: a^4 - b^4 = (a - b)(a + b)(a^2 + b^2) utilizing authentic numbers a^4 - b^4 = (a - b)(a + b)(a - bi)(a + bi) utilizing complicated numbers
2016-12-08 19:13:50 · answer #7 · answered by fuchser 4 · 0⤊ 0⤋
FOIL method
First
Outside
Inside
Last
1.x2-12x+36
(x-6)(x-6)
2.16b4 -1
(4b^2-1)(4b^2+1)
factor out (4b^2-1) = (2b+1)(2b-1)
put it all together = (2b+1)(2b-1)(4b^2+1)
2007-06-26 05:43:51 · answer #8 · answered by Carmen 4 · 0⤊ 2⤋
how can u learn if u shimmy off all ur homework to yahoo answers. Look through yourr books for directions, and if you still don't know how to do them, ask your teacher for help.
2007-06-26 05:44:13 · answer #9 · answered by Postman 2 · 0⤊ 2⤋