A sphere(radius 3cm) dropped in a watery cylinder(radius 6cm),sphere will submergd what'l be the surface level

Question

A sphere of radius 3 cm is dropped in to a cylindrical vessel partly filled with water. the radius of the vessel is 6 cm. If the sphere is submerged completely,by how much will the surface of water be raised .Options are (1)1 cm, (2) 2 cm, (3)3 cm, (4)6 cm

Answer 1

Volume of sphere is 4/3 pi r cubed; where r = 3.
So volume of sphere is 4/3 times 27 pi = 108/3 pi = 36 pi

So the previous volume of water in the cylinder now taken up by the sphere is 36pi.

The cylinder has radius 6cm and extra volume required is
pi r squared h - where r is 6 and h is what we want to find.

So 36 pi h = 36 pi
So h = 1cm

Answer (1) 1cm.

Answer 2

Volume of sphere = volume of water displaced.
4/3 pi r^2 = pi R^2h where r = radius of sphere = 3 cm, R = radius pf cylinder = 6 cm and h = height of water raised.
so 4/3 × 3^3 = 6^2 × h
solving h = 1 cm ----option (1)

Answer 3

Volume of a Sphere = 4/3¶r3 = 4/3 x ¶ x (3 x 3 x 3)

= 36 ¶

Volume of Cylinder = ¶r2h = ¶ x (6 x 6) x h

= 36 ¶h

36 ¶ = 36 ¶h

h = 1 cm

Answer 4

by using a million/5 if the dimensions of sphere and cylinder are equivalent and the water rises precisely, through fact the quantity of sphere is strictly a million/4 of the quantity of the cylinder, the entire quantity would be 5/4 of the unique cylinder quantity, it truly is a million/5 longer

Answer 5

the volume of the sphere is:
4/3*pi*r^3
4/3*pi*27=113,09
to get the height of a cylinder that volume (that would be how much the water raises) you have to devide this by the base area of the cylinder which is r^2*pi = 36*pi=113,09
113,09/113,09=1
option 1 is correct

Answer 6

I think it's 1cm.

I have some working but it's difficult to explain. I feel as if the question needs to be explained better. I don't know.