physics sum on average velocity??

Question

An athelete swims a length of 50 m in a pool in 20 seconds.
and make his return trip to the starting position in 22 seconds.
detemaine his average velocity:
1.first half of the swim
2.second half of the swim
3.round the trip.
kindly solve it and explain

Answer 1

Bit of a problem here. Velocity is change in position divided by time take, so the average velocity for the swim in total is zero.
If we take the problem in two parts:

1. first half - average velocity is Δx/Δt = 50/20 = 2.5 m/s to the left (say)

2. second half - average velocity is Δx/Δt = -50/22 = -2.27 m/s (which is 2.27 m/s to the right)

IN THIS CASE, SO FAR, AVERAGE VELOCITY AND AVERAGE SPEED ARE THE SAME VALUES (different signs)

3. Average velocity is zero (see start). HOWEVER, average SPEED is DISTANCE travelled / time taken = 100 / 42 = 2.38 m/s

Hope this helps

Answer 2

Average speed = Distance / time

First half of the swim - 50 m in 20 seconds = 50 / 20 = 2.5 m/s

Second half of the swim - 50 m in 22 seconds = 50 / 22 = 2.27 m/sec

Round trip = Distance is 100 m and time taken 42 secs.

100 / 42 = 2. 38 m/sec

you will see that it is also obtained by adding the two average speeds and dividing by two.

2.5 + 2.27 = 4.77/2 = 2.385 m/sec.

But the first method is correct if the distances are not equal.

And yes, your problem makes sense if you talk of speeds which are scalar quantities and not velocities, which are vectors. The Old School Teacher is correct in that the average velocity of the round trip is Zero. But I think you meant speed and not velocity.

Answer 3

for 1st half
Total distance 50 m
total time take 20sec

Av velocity for 1st half 50/20
= 2.5 m/sec

similarly av velocity for another half 50/22
2.2727 m/sec

Av velocity for whole travel= total distance travelled/total time taken

(50+50)/(20+22)

= 100/42
=2.381 m/sec ANSWER

Answer 4

The formulation is d = v*t so which you recognize that the entire distance, divided by utilising the entire time, is one million.11 m/sec. "because of the fact she hikes for 6.ninety one km with a median velocity of two.sixty two m/s due west" d = v*t will inform you approaches a lot time this took. keep in mind that d could be in meters if v is in m/sec. "and hikes with a median velocity of 0.677 m/s due east" d = v*t you do no longer know d or t for that 2nd holiday. permit's call them d_E and t_E for distance traveled east and time traveled east. So d_E = 0.677 * t_E What do you recognize? you recognize that the entire distance divided by utilising the entire time is one million.11 m/sec. So what do you get in case you employ that suggestions? the entire distance is 6.ninety one km plus 0.677*t_E. the entire time is the time from the westward area (calculated above) plus t_E. Divide those and set them equivalent to one million.11 m/sec. you presently have an equation with basically one unknown, t_E, so which you will resolve it for that unknown. then you certainly can use that to locate d_E.

Answer 5

Velocity is speed over time.

1. 50m/20s = 2.5m/s

2. 50m/22s = 2.27m/s

3. 50 + 50 = 100m
20 + 22 = 42s

100m/42s = 2.38m/s

Answer 6

d only possible one is rond d trip.
fist half=nil cos in 25m u cant quarantee a steady ,constant swim he slows down,comes up dependin.it cant b 10s for 25m
3]velo=dist/tyme
=====5o/20;;;;;;;;;first
=======50/22
avera=[50+50]/{20+22}
=====100/42
avera=2.4m/s