2007-06-25 23:11:28 · 8 answers · asked by undine 2 in Science & Mathematics ➔ Physics
just using the diameter and its thickness??? help!
2007-06-25 23:23:59 · update #1
Just using the diameter (d) and thickness (t)
V = t * (pi) * (d/2)^2
Basically, take the area of a circlue and multiply it by the thickness.
2007-06-25 23:26:03 · answer #1 · answered by Anonymous · 1⤊ 0⤋
Since coins are not sooth and consistent you can only approximate by measuring. the approximate volume is pi(r^2)h when r is the radius and h is the thickness of the coin.
To get the actual volume you will need to measure it by displacement. If you drop the coin into a known volume of fluid the difference in the volume of the combined masses is directly attributable to the coin.
2007-06-26 01:21:50 · answer #2 · answered by Brian K² 6 · 0⤊ 0⤋
If you know the diameter, you can halve it to get the radius.
Now, you have both the radius and the thickness. A coin is a cylinder, with the thickness as its height.
So, you can use the formula for the volume of a cylinder,
Volume = pi*r^2 * h
where r is the radius.
2007-06-25 23:38:54 · answer #3 · answered by Bhaskar 4 · 1⤊ 0⤋
Drop one or more coins in a measuring beaker or if that is too narrow to accept the coins, drop them carefully into a large beaker or some other container filled to the brim with water and collect the overflow into a measuring jar.
Divide the volume of water by the number of coins to get the volume of a coin. All the coins must be of one type if you are using more than one coin. Using more coins reduces the experimental error.
2007-06-25 23:20:36 · answer #4 · answered by Swamy 7 · 0⤊ 2⤋
maximum funds are extremely small in length. utilizing a unit this is great whilst in comparison with the actual length of the coin leads to inconveniently small length values. Likewise utilizing a unit this is small whilst in comparison with the dimensions of the coin leads to inconveniently large values. Millimeters (or cubic millimeters for quantity) seems to be the main suitable determination, whether it quite relies upon on the actual length of the coin. I bear in mind examining approximately one way of lifestyles that used funds that have been approximately the dimensions of truck wheels. For those funds, decimeters or perhaps meters ought to be the logical determination.
2016-12-08 19:02:21 · answer #5 · answered by Anonymous · 0⤊ 0⤋
get a small graduated cylinder with small graduation so that it can measure the nearest cu.cm
fill the cylinder with water to exact reading
dip / subemrged the coin inside the cylinder
water will rise up and the reading of volume will increase
the difference in volume readings is the required volume of the coin
2007-06-25 23:22:42 · answer #6 · answered by CPUcate 6 · 0⤊ 2⤋
Take a full glass of water. And a plastic (clean) syringe with liquid volume marks on it. Glass must be filled with water completely and exactly. Then gently put the coin in glass. Collect all excessive water which spilled from the glass with syringe and see the volume.
2007-06-25 23:18:43 · answer #7 · answered by rexxyellocat 5 · 0⤊ 2⤋
fill a Beaker with a know level of water, put the coin into it, take the final measurement and make the subtraction. if the level doesn't change apparently, put into it more coins and make the final division. for example, for 100 coins, you need to make the subtraction and divide the results by 100
2007-06-25 23:20:00 · answer #8 · answered by LENNONLNX0618 2 · 0⤊ 2⤋