Can YOU prove that 5 is equal to 2?
Hint: Use mod.
2007-06-25 22:55:29 · 9 answers · asked by βread⊆ℜumbs™ 5 in Science & Mathematics ➔ Mathematics
Asking cause some AP calculus teacher who used to be a Rocket Scientist in my school proves numbers to be equal to each other all of the time. 5=2. 32=54
I do not know if it is right, but my school has a reputation to have sucky teachers. Therefore, I too disbelieve it.
2007-06-25 23:06:46 · update #1
All such proofs are defective. If you give the proof, I am sure to tell you the defect.
Most of them involve incorrect mathematical operation like dividing by zero or taking square-root on both sides. When you take sq. rt. of both sides of equation, then one side is +- of the other. One of + or - is incorrect. Normally such proofs consider + sign where - sign makes both sides equal.
2007-06-25 23:14:44 · answer #1 · answered by Madhukar 7 · 2⤊ 0⤋
Yeah, you can use mod(3), but then 5 really isn't defined there is it?
I could do proofs where you are really proving that 5 times zero equals 2 times zero or 5 times infinity equals 2 times infinity, classic tricks.
If "5" and "2" are strings and "equal" is a logical function in some high-level computer programming or scripting languages, "5 equal 2" is true.
Consistent with your mod hint, if each integer represents a rotation of an equilateral triangle by one side clockwise about its center, then indeed 5=2 ..... as also do 3=0, -1=2, 3n + k = k for (k,n) integers.
2007-06-26 06:11:15 · answer #2 · answered by jcsuperstar714 4 · 0⤊ 0⤋
The easiest way is as follows:
5 * 0 = 0 : True
2 * 0 = 0 : True
=> 5 * 0 = 2 * 0 : True
Divide by 0 - which is of course the silly step!
5 = 2!
2007-06-26 06:10:34 · answer #3 · answered by welcome news 6 · 1⤊ 1⤋
Choose arbitrary a and b, and let t = a + b.
(a + b)(a - b) = t(a - b)
a^2 - b^2 = ta - tb
a^2 - ta = b^2 - tb
a^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4
(a - t/2)^2 = (b - t/2)^2
a - t/2 = b - t/2
a = b
(5+2)(5-2) = 7(5-2)
5^2 - 2^2 = (7x5) - (7x2)
5^2 - (7x5) = 2^2 - (7x2)
7^2 - (7x5) + (7^2)/4 = 2^2 - (7x2) + (2^2)/4
(5 - 7/2)^2 = (2 - 3/2)^2
5 - 7/2 = 2 - 7/2
5 = 2
The trick to most of these is that you hide a spot where you divide by zero.
2007-06-26 06:17:23 · answer #4 · answered by JK (the Cosmic Jester) 2 · 1⤊ 0⤋
you have sucky teachers... lol...
2+3 = 1+1
5 = 2
2007-06-27 06:07:12 · answer #5 · answered by D3L1V3RYB0Y 1 · 1⤊ 0⤋
Whatever be the method or proof, that will be wrong. 5 is not equal to 2.
2007-06-26 06:01:51 · answer #6 · answered by Swamy 7 · 1⤊ 0⤋
? maybe flip over the number 5 and you will get a bizarre number 2... think in your question men!!!!!!!
2007-06-26 06:05:24 · answer #7 · answered by LENNONLNX0618 2 · 0⤊ 0⤋
If you in any methods prove that 5 = 2 then... please let me know. i will like to know.
2007-06-26 06:04:56 · answer #8 · answered by Sindhoor 2 · 0⤊ 0⤋
I dont feel like it.
2007-06-26 06:03:45 · answer #9 · answered by Lindsey 1 · 0⤊ 1⤋