3x^2-33=0
I think the answers are: sqrt11 and -sqrt11. Am I right? Could you also explain how you got your answer?
2007-06-25 17:24:24 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
there has to be two answers, i came up with sqrt 11 and -sqrt 11 are both of them correct?
2007-06-25 17:32:49 · update #1
3x^2 - 33 = 0
3x^2 = 33
x^2 = 11
x = +/- sqrt(11)
you're right!
2007-06-25 17:37:28 · answer #1 · answered by 7 · 0⤊ 0⤋
3x² = 33
x² = 11
x = 屉11
Explanation
â11 x â11 = 11 and 3 x 11 = 33
(-â11) x (-â11) = 11 and 3 x 11 = 33
2007-06-26 14:45:47 · answer #2 · answered by Como 7 · 0⤊ 0⤋
yes your answers are correct!
3x^2-33=0
- move 33 to the other side
3x^2=33
- divide both sides by 3
x^2=11
- square root both sides to solve for x
âx^2 = â11
therefore x = +/- â11
2007-06-26 00:38:50 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Add 33 to both sides:
3X^2=33
Divide by 3:
X^2=11
Sqrt:
Sqrt(X^2)=Sqrt(11)
Simplify:
X=Sqrt(11)
Yes, you got the right answer
2007-06-26 00:28:47 · answer #4 · answered by Anonymous · 0⤊ 1⤋