2007-06-25 15:53:02 · 6 answers · asked by westsideslider1979 1 in Science & Mathematics ➔ Physics
An object dropped from an airplane or any high point falls at the rate of 32 ft per second per second until it reaches its "terminal velocity"
1 second = 32ft
2nd second = 64ft
3rd second = 128 ft
4th second = 256 ft
etc. until terminal velocity is reached.
for the human body, depending on your angle of fall is approximately 125 miles per hour.
2007-06-25 16:02:51 · answer #1 · answered by pinelake302 6 · 0⤊ 0⤋
I can personally tell you from experience that terminal velocity for a person in the "arched position" is about 120 mph. I am a skydiver, so I have tracked my fall as I jumped. In addition, I attend Case Western Reserve University and have done the physics to prove this property of freefall.
2007-06-26 00:02:00 · answer #2 · answered by C-Wryte 3 · 0⤊ 0⤋
Terminal velocity
2007-06-25 22:55:49 · answer #3 · answered by Dave B 2 · 0⤊ 0⤋
Terminal velocity.
2007-06-29 12:16:06 · answer #4 · answered by johnandeileen2000 7 · 0⤊ 0⤋
Hi. Terminal velocity. Depending on how you hold your body, anywhere from 125-185 MPH.
2007-06-25 22:55:48 · answer #5 · answered by Cirric 7 · 0⤊ 0⤋
It's called 'Terminal Velocity'.
2007-06-25 22:55:32 · answer #6 · answered by Norrie 7 · 0⤊ 0⤋