A uniform diving board, of length 5.0 m and mass 54 kg, is supported at two points; one support is located 3.4 m from the end of the board and the second is at 4.6 m from the end (see the figure below). What are the forces acting on the board due to the two supports when a diver of mass 62 kg stands at the end of the board over the water? Assume that these forces are vertical. [Hint: In this problem, consider using two different torque equations about different rotation axes. This may help you determine the directions of the two forces.]
2007-06-25 15:45:16 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Physics
The weight of the board is (54)(9.81) N centered 2.5 m from either end. The weight of the diver is (62)(9.81) N. The force on the board by the near support is
F1 = ((62)(9.81)(4.6) + (54)(9.81)(4.6 - 2.5))/(4.6 - 3.4)
F1 = (2797.812 + 1112.454)/1.2
F1 = 1,405.298 N upward
The force on the board by the far support is
F2 = 9.81((62)(3.4) + (54)(0.9))/1.2)
F2 = 2,120.595 N downward
2007-06-25 19:15:45 · answer #1 · answered by Helmut 7 · 0⤊ 1⤋