a train goes forward at a speed of 1 m/s for 20 sec.then it stopsand goes backwards at a speed of 0.5 m/s for 4 seconds.after both movements are completed. howfar is the train located from its starting point. (only asking for the trains final location,not the total distancethat it travled) my answer was 19 ? other possible answers are 18 m
20 m 22m
2007-06-25 15:39:32 · 4 answers · asked by treasure 2 in Science & Mathematics ➔ Physics
18m
20sec * 1m/sec = 20m
-0.5m/sec * 4sec = -2m
20m - 2m = 18meters
2007-06-25 15:45:26 · answer #1 · answered by mrlexington 2 · 0⤊ 0⤋
If you go forward at 1 m/s for 20 s, then you have gone forward 20 meters.
x = v*t
x = (1 m/s)*(20 s)
x = 20 m
If you go backward at 0.5 m/s for 4 s, then you have traveled...
x = v*t
x = (-0.5 m/s)*(4 s)
x = -2 m
So, you've gone 20 meters forward, then 2 meters backwards. You are now 18 meters from where you started.
2007-06-25 22:51:37 · answer #2 · answered by lithiumdeuteride 7 · 0⤊ 0⤋
18 m
(20 x 1) - (.5 x 4)
20-2
18
2007-06-25 22:47:01 · answer #3 · answered by almostawake 1 · 0⤊ 0⤋
in forward moving the distance was 20 meter,then it goes back 2 meter,so it is 18 meter
2007-06-25 22:52:55 · answer #4 · answered by Anonymous · 0⤊ 0⤋