Question for math wizards, very hard?

Question

Solve 1/F=1/w + 1/r for r

Answer 1

1/F = 1/w + 1/r
1/F - 1/w = 1/r
w/Fw - F/Fw = 1/r
(w - F)/Fw = 1/r
Fw/(w - F) = r

Note that this answer is the same as "1/(1/F - 1/w)" but simplified.

Answer 2

Throw all terms not containing r on one side of the equation:

1/r = 1/F - 1/w

Then you want to take the reciprocal of both sides. Fix up the right-hand side so that it is (some number)/(another number). I mean, give it a common denominator:

1/r = (w - F)/(Fw)

then "flip":

r = (Fw)/(w-F)

Answer 3

the line that rises 12 ft vertically for each 60 ft horizontally is steeper. i'm going to even do the maths for you!!! 5/70 divided by utilising 5/5 (fairly one million) equals one million/14. 12/60 divided by utilising 12/12 (additionally fairly one million) equals one million/5. think of the two roads going on horizontally. One is going down 14 ft and the different is going down 5 ft. Now, think of the roads the two going up vertically one million foot from the element they only stopped. Repeat that technique from the element you left off with. It feels like the single going 14 ft horizontally is steeper (by utilising a protracted shot, by utilising the way, very almost three times steeper). i'm hoping this helps!!! :)

Answer 4

1/F=1/w + 1/r for r

subtract 1/w from both sides
1/F - 1/w =1/r for r

multiply both sides by r
r(1/F - 1/w) = 1

add the fractions inside the parenthesis together
r (w-F)/(Fw) = 1

multiply both sides by (Fw)/(w-F)
r = (Fw)/(w-F)

There you go!

Answer 5

first you subtract 1/w on both sides:
1/F-1/w=1/r
then you multiply both sides by r:
r(1/C-1/p)=r/r
simplify r/r
r(1/C-1/p)=1
then divide both sides by(1/F-1/w):
r=1/(1/C-1/p)
finally you divide everything out:
r=C-p

Answer 6

1/r = 1/F - 1/w
r/r = r(1/F - 1/w)
r = 1/(1/F - 1/w)

Answer 7

Multiply each term by Fwr.
wr=Fr+Fw
wr-Fr=Fw
r(w-F)=Fw
r=Fw/(w-F)

Answer 8

1/r = 1/F - 1/w
1/r = (w - F) / Fw
r = (Fw) / (w - F)

Answer 9

1/r = 1/F - 1/w
= (w-F)/(Fw)
r = Fw / (w - F)

Answer 10

r= (FW) / (W-F)

Comes from

1/f=1/w+1/r ... multiply everything for fwr on both sides

wr=fr+fw ----> wr-fr=fw -----> r(w-f)=fw ----> r= fw/(w-f)