a 220 kg speedboat is negotiating a circular turn (radius = 52m) around a buoy. during the turn the engine causes a net tangential force of magnitue 550 N to be applied to the boat. the initial tangential speed of the boat going into the turn is 5.0 m/s
(a) find the tangential acceleration
(b) after the boat is 2.0 s into the turn, find the centripetal acceleration
2007-06-25 13:46:41 · 3 answers · asked by lub1210 1 in Science & Mathematics ➔ Physics
Tangential acceleration = F/m = 550 / 220 = 2.5m/s^2.
Tangential velocity after 2 s is, v = ut + 0.5at^2
v = 5*2 + 0.5 * 2.5 * 4 = 15 m/s
Centripetal acceleration is mv^2 /R = 220 * 15*15 / 52 = 105.77 N
2007-06-25 17:40:01 · answer #1 · answered by Pearlsawme 7 · 0⤊ 3⤋
(a) Use Newton's Law to find the tangential acceleration from the tangential force.
(b) Find the new tangential velocity, which will allow you to find the centripetal acceleration.
2007-06-25 14:06:50 · answer #2 · answered by msi_cord 7 · 0⤊ 1⤋
can u plz post this at http://www.tutorbuddy.org i will answer when u post
2007-06-25 14:08:37 · answer #3 · answered by Anonymous · 0⤊ 1⤋