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I really don't get the passer rating. I've read about it on the internet, but i need someone to explain it to me in English please?

2007-06-25 13:45:00 · 4 answers · asked by Anonymous in Sports Football (American)

4 answers

* The component for completion percentage, C, is calculated as: (COMP \ATT) X 100 - 30 \20

* The component for yards per attempt, Y, is calculated as: ((YDS \ATT) - 3) X .25

* The component for touchdowns per attempt, T, is calculated as: (TD \ATT) X 20

* The component for interceptions per attempt, I, is calculated as: 2.375 - ( INT \ATT x 25)

The four components are then added, divided by 6, and multiplied by 100. Thus, the formula for passer rating can be given as:

(( (C + Y + T + I) \ 6) X100)

Perfect QB Rating in the NFL is 158.3


NCAA
(100 * Completion %) + (8.4 * Yds per att) + (330 * Td %) - (200 * Int %).



hopefully that counts as English :]

2007-06-25 14:04:44 · answer #1 · answered by Chloroform Smile 2 · 0 0

Although the formula is complicated to a point and the actual number makes little sense its essentially a measure of QBs across four categories: completion percentage, yards per attempt, TD passes per attempt, and interceptions per attempt. Is that what you were looking for pr are you wondering how the number is derived?

2007-06-25 13:50:34 · answer #2 · answered by Fantasy Sports Dude 2 · 0 0

It is a way of measuring how effective a quarterback is. It is calculated by using pass attempts, number of completions, touchdowns thrown, interceptions thrown, and yards thrown for. It is a very complicated calculation. There are essentially four components: Completion percentage (C), yards per attempt (Y), touchdowns per attempt (T), and interceptions per attempt (I). These calculations are shown in my citation.

2007-06-25 13:57:03 · answer #3 · answered by msi_cord 7 · 0 0

geez..chloroform are you the Rainman?

that passer rating has never meant anything..in the terms of W-L...Ben Rotheilsberger and Kyle Orton can attest to that.

2007-06-25 14:52:21 · answer #4 · answered by Anonymous · 0 0

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