What is the antiderivative of
e^ -3/5
please know what your doing, this is Calculus
2007-06-25 13:37:20 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
scratch that!!!!!!
75e^ -3/5
is what i meant to say :D (I'm very silly sumtimes)
2007-06-25 13:38:55 · update #1
e^(-3/5) is a constant
antiderivative is e^(-3/5)x + C
2007-06-25 13:42:21 · answer #1 · answered by holdm 7 · 2⤊ 1⤋
If holdm read the amended question, he'd say 75e^(-3/5) is STILL a constant, so its antiderivative is
[75e^(-3/5)]x + c,
and my TI-89 agrees.
2007-06-25 20:51:12 · answer #2 · answered by Philo 7 · 1⤊ 0⤋
75e^(-3/5) is a constant, so the antiderivative is:
[75e^(-3/5)]*x + C
2007-06-25 20:49:51 · answer #3 · answered by Lee 3 · 0⤊ 1⤋
INT [75e^(-3/5)] dx
= [ 75e^(-3/5) ]x + C
Answer: [ 75e^(-3/5) ]x + C is the antiderivative of 75e^(-3/5).
2007-06-25 20:43:41 · answer #4 · answered by mathjoe 3 · 0⤊ 3⤋
75e^-3/5 is a constant
â«cdx=cx
â«(75e^-3/5)dx=75e^-3/5)x
2007-06-25 20:50:49 · answer #5 · answered by yupchagee 7 · 0⤊ 1⤋
The antiderivative (indefinite integral) of 75 e^-3/5 is (75/(-3/5))e^-3/5, which simplifies to -125e^-3/5.
2007-06-25 20:45:42 · answer #6 · answered by zee_prime 6 · 0⤊ 3⤋
if there is no variable in the argument then the antiderivative (integral) is 75xe^-3/5 + c, using your amended question.
2007-06-25 20:44:37 · answer #7 · answered by John V 6 · 1⤊ 2⤋
75x/e^(3/5)
2007-06-25 20:41:59 · answer #8 · answered by Mark S, JPAA 7 · 0⤊ 2⤋