is -5>than square root of -5?
2007-06-25 12:02:24 · 10 answers · asked by Jake 1 in Science & Mathematics ➔ Mathematics
+/-sqrt(5)i, where i = sqrt(-1)
2007-06-25 12:05:58 · answer #1 · answered by hawkeye3772 4 · 0⤊ 0⤋
Have to use i² = - 1
√(- 5) = √(5 i²) = √5 i
2007-06-29 07:30:28 · answer #2 · answered by Como 7 · 0⤊ 0⤋
A negative number can not have a square root bc a square root is a number multiplied by the same number gives you that certain number, but there are no two exact numbers that can give u -5. You get a negative number by multipling a negative times a positive n there for there is no square root of -5. A negative times a negative gives you a positive.
2007-06-25 12:09:43 · answer #3 · answered by Anonymous · 0⤊ 0⤋
The square root of any negative number is imaginary.
i*(square root of 5)
2007-06-25 12:07:57 · answer #4 · answered by Linduh. 3 · 0⤊ 0⤋
i* square root of 5 = square root of -5, -5 is larger on a complex plane (magnitude)
2007-06-25 12:05:13 · answer #5 · answered by lxl_fro_lxl 2 · 0⤊ 0⤋
√(-1)√(5) =
i√(5)
2007-06-25 12:06:51 · answer #6 · answered by MathGuy 6 · 0⤊ 0⤋
sqrt(-5) = sqrt(5i^2) = i sqrt(5).
You cannot compare -5 with sqrt(-5). The former is a real number, and the latter an imaginary one. Neither is greater or less than the other.
2007-06-25 12:07:56 · answer #7 · answered by Anonymous · 0⤊ 0⤋
Hi. Look and learn! Type "sqrt (-5)" into Google.
sqrt(-5) = 2.23606798 i
2007-06-25 12:07:34 · answer #8 · answered by Cirric 7 · 0⤊ 0⤋
sqrt(-5)
2.236067977499789696409
173668731276235440618359
611525724270897245i
2007-06-25 12:10:09 · answer #9 · answered by Anonymous · 0⤊ 0⤋
i dunno! l0l
2007-06-25 12:09:41 · answer #10 · answered by Anonymous · 0⤊ 0⤋