(x-4)(x-1)
x^2 - 5x + 4
to get to there, use FOIL as your aid.
FOIL stands for:
First
Outside
Inside
Last
1st, you multiply x in the first parenthesis by x in the second parenthesis. Now, you should have x^2
2nd, you multiply x in the first parenthesis by -1 in the second parenthesis. Now you should have x^2 - x
3rd, multiply -4 in the first () by x in the second (). Now you should have x^2 - x - 4x
4th, multiply -4 in the first () by -1 in the second (). Now you should have x^2 - x - 4x + 4
5th, add like terms.
final answer: x^2 -5x + 4
2007-06-25 10:22:16
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answer #1
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answered by Carmen 4
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You need to take x-4 and multiply it by each part of the send parenthesess.
So (x*(x-4))-(1*(x-4))
(x^2-4x) -( x-4)
X^2-5x+4 (Note that -4x - x = -5x and the -4 and the negative sign just in front of that parenthese makes it + 4)
2007-06-25 17:27:16
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answer #2
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answered by Katie 3
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Break it down step-by-step like this to see how to do this type of problem more clearly:
(x - 4)(x -1)
x(x-1) - 4(x-1)
x^2 - x - 4x + 4
x^2 - 5x + 4
2007-06-25 17:26:11
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answer #3
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answered by coryfucius 3
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(x-4)(x-1)
Just split the parenthasis:
x(x-4) - 1(x-4)
x^2-4x - x+4
Simplify:
x^2-5x+4
Hope that helped!
2007-06-25 17:26:37
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answer #4
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answered by Sugar 2
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= x.(x - 1) - 4.(x - 1)
= x² - x - 4x + 4
= x² - 5x + 4
2007-06-28 05:07:59
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answer #5
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answered by Como 7
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multiply x to ( x - 1) = x^2 - x
multiply -4 to ( x - 1) = - 4x + 4
add. . x^2 - x . . and . . - 4x + 4
answer is . . . x^2 - 5x + 4
2007-06-25 17:33:30
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answer #6
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answered by CPUcate 6
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(x-4)(x-1) = x(x) -1(x) -4(x) -4(-1)
2007-06-25 17:25:37
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answer #7
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answered by koutetsu12 3
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(x-4)(x-1)
= x*x +x*(-1) -4*x -4*(-1)
= x^2 -x -4x +4
= x^2-5x +4
2007-06-25 17:24:34
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answer #8
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answered by ironduke8159 7
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x^2 - 5x + 4 is the answer.
2007-06-29 13:26:58
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answer #9
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answered by Jun Agruda 7
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(x-4)(x-1)=x^2-5x+4. answer
2007-06-25 17:21:39
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answer #10
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answered by Anonymous
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