I got really stuck with this can someone help, i am rotton at maths
2007-06-25 09:51:52 · 4 answers · asked by pud 1 in Science & Mathematics ➔ Chemistry
so you are looking for pH then? Then take the - log of 0.32. And thats the answer.....
2007-06-25 09:59:42 · answer #1 · answered by Anonymous · 0⤊ 1⤋
Atomic weights: H=1 N=14 O3=48 HNO3=63
I take your question to be the [H+] when the HNO3 is dissolved in enough water to make 1 L. Let nitric acid be called N. Let the solution be called S.
0.32gN/1LS x 1molN/63gN = 5.16 x 10^-3molN
Because HNO3 is a strong acid, the [H+] = [HNO3] = 5.16 x 10^-3.
I think that they wanted to have the pH of such a solution, but you didn't ask that.
2007-06-25 10:11:49 · answer #2 · answered by steve_geo1 7 · 0⤊ 0⤋
Molecular weight of HNO3 = 63
0.32g = 0.005M = H ion conc since HNO3 is a strong acid.
2007-06-25 10:01:50 · answer #3 · answered by Jabberwock 5 · 0⤊ 0⤋
work on your english first!!!! idk...lol...jfk.
2007-06-25 10:00:57 · answer #4 · answered by oinkbuns 2 · 0⤊ 0⤋