I need help with creating a chart and solving this problem.?

Question

I'm confused.

SOMEHOW I have to:
Step 1. Show the values in the chart.
Step 2. Show the equation.
of this problem...

Alan and Dave leave from the same point driving in opposite directions, Alan driving at 55 miles per hour and Dave at 65 miles per hour. Alan has a one-hour head start. How long will they be able to talk on their cell phones if the phones have a 250-mile range?
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For the chart I have to use:
general headings - rate per item - # of items total - total

So for general headings, I use Alan in one column and Dave in the other. Do I need anything else under general headings? How do I do the rest of the problem? I am so very confused!

THANKS FOR YOUR HELP!

Answer 1

General - (Rate)- (items total)- total
Alan- (55) - (X+1)- (55x +55)
Dave- 65- X - 65x


55x+65x+55=250
120x=195
x=1.63
1hour and 37minutes and 48seconds this is after Alan's head start of 1 hour, so add another hour to this

final answer = 2.63 or 2 hours 37 minutes and 48 sec

Answer 2

Distance = rate x time

First Column: Hours
Second Column: Dave's Distance (rate x time)
Third Column: Alan's Distance (rate x time)

Hours ....... Dave ........ Alan........Total Distance.

...0..............65(0)......... 55(0)...............0
...1..............65(0)......... 55(1).............55 miles
...2..............65(1)......... 55(2)...........175 miles
...3..............65(2)......... 55(3)...........295 miles

Using the table, you can see that they can talk more than 2 hours but less than 3 hours.
To find an exact answer, use a t for the time to write expressions for the distance Dave and Alan Drove

...t..............65(t - 1).......55(t)...........65(t - 1) + 55t miles

Set the expression equal to 250 and solve for t.

65(t - 1) + 55t = 250
65t - 65 + 55t = 250
120t - 65 = 250
120t = 315
t = 2.625

They can talk for 2.625 hours or 2 hours, 37 minutes and 30 seconds

Answer 3

first, they both travel at a constant speed, the formula is:

distance = speed * time or just x = vt

let t be the time Alan left, because Dave left after 1hr Alan, his time is t - 1.

x (Alan) = vt
x (dave) = v( t - 1)

we know that spee of Alan is 55 mi/hr, and speed of Dave is 65mi/hr. Plug them in the equation

x (Alan) = 55t
x (dave) = 65(t - 1)

because they both travel in opposite direction, at a certime time, their distances will add to 250 mile
x (Alan) + x (dave) = 250

55t + 65(t - 1) = 250
55t + 65t - 65 = 250
120t = 315
t = 2.625 hr

Answer 4

This is a trick question.

Cell phone technology doesn't depend on the distance between the two end points. It only matters how far each of the end points are from the current cells base station. As long as they stay driving are within their networks cover area, they will be able to talk until the batteries run out (or fuel in the car, if they are on chargers (or fuel available at gas stations to power the car and car battery.))

Answer 5

You can't really do tables on Yahoo, more's the pity. I hope you can read this.

. . . . . rate . . . . . . start time. . . distance
Alan . .55 mph . . . 0 . . . . . . . . . 55 * x
Dave . .65 mph. . . 1 . . . . . . . . . 65 * (x - 1)

What you need to solve is what is x when
65(x -1) - 55(x) = 250

65x - 65 - 55x = 250
10x = 315
x = 31.5 hours

They'd better pack throat lozenges.

Answer 6

Really, the question should say 2-way radio, because their cell phones will eventually start using different cell towers once they have gone far enough.