What do (-4a^5b)^2 =?

1 ⤊

2007-06-25 06:15:35 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

(-4a^5b)^2
= 16 a^10 b^2

2007-06-25 06:18:46 · answer #1 · answered by sweet n simple 5 · 1⤊ 0⤋

(-4a^5b)^2
distribute the ^2 to each of the numbers or variables inside
-4^2a^5(2)b^2
16a^10b^2

2007-06-25 06:21:35 · answer #2 · answered by Carmen 4 · 0⤊ 0⤋

I suppose it is (-4a+5b)^2 isnt it?
If it is yes then :
(-4a+5b)^2=(16a^2+25b^2-40ab)

If it is not then :
(-4a^5b)^2=(-4a)^10b

2007-06-25 06:20:36 · answer #3 · answered by seed of eternity 6 · 0⤊ 0⤋

Assume question is:-
[ (- 4).(a^5).b ] ² = 16.a^(10).b²

2007-06-28 22:55:15 · answer #4 · answered by Como 7 · 0⤊ 1⤋