2007-06-25 05:53:09 · 12 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
8 in
2007-06-25 05:55:40 · answer #1 · answered by Anonymous · 2⤊ 0⤋
The area of a square is found by multiplying the length of 2 sides. If each side of a square is length x, then the area of a square is x^2. So if the area of a square is 64, then:
x^2 = 64
x = sqrt(64) (meaning the square root of 64)
x = 8
Here's how to check your work:
x^ 2 = 64
if x = 8, then
8^2 = 8 x 8 = 64
2007-06-25 05:59:55 · answer #2 · answered by N E 7 · 0⤊ 0⤋
Area of a square is side times by side. So, in an equation we can say A=x^2.
Now, we have the area, 64, and we need the sides.
Next you plug in the area, A=64. So, new equation is 64=x^2.
Now, take the square root of 64, and you get 8 which equals 8.
Length of each side equals 8. Hope this helps out.
2007-06-25 06:02:14 · answer #3 · answered by JJ 4 · 1⤊ 0⤋
Area of a square = Side ^2
64=Side^2
Side= Square Root (64)
Side=8 inches
2007-06-25 05:57:16 · answer #4 · answered by WD 2 · 0⤊ 0⤋
since it is a square, all sides are 8in
because the square root of 64 is 8
2007-06-25 05:56:34 · answer #5 · answered by Carmen 4 · 0⤊ 0⤋
formula for finding area of square is
(length of one side)^2=area
so work if backwards if you know the area you can find the length of the side:
length of one side = square root(area)
square root of 64 is 8<---
2007-06-25 05:58:21 · answer #6 · answered by datscold 1 · 0⤊ 0⤋
sqrt 64=8 inches
2007-06-25 05:57:22 · answer #7 · answered by fofo m 3 · 0⤊ 0⤋
SqRoot of 64 = 8 in.
2007-06-25 06:01:32 · answer #8 · answered by Anonymous · 0⤊ 0⤋
For a square, A = s^2 A= area, s=length. Work it out.
For a parallelogram in general, A=(a)(b)[sin(theta)] where a,b are the sides, theta is the angle of intersection.
2007-06-25 05:56:39 · answer #9 · answered by Uncle Al 5 · 0⤊ 0⤋
A = s^2 where s is a side
64=s^2
8 = s
2007-06-25 05:57:33 · answer #10 · answered by ironduke8159 7 · 1⤊ 0⤋