Five resistors with resistance R1 = 2.00 ohm, R2 = 2.00 ohm, R3 = 3.00 ohm, R4 = 7.00 ohm, R5 = 4.00 ohm, are connected to a battery with emf = 9.00 V as shown in the figure.
1- What is the current in resistor R1?
2-What is the current in resistor R2?
3-What is the current in resistor R3?
4-What is the current in resistor R4? 5-
5-What is the current in resistor R5?
6-What is the potential difference between the points P and P'?
the figure : http://www5.0zz0.com/2007/06/25/09/15627721.gif
2007-06-25 04:54:38 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics
Let's build equations using ohm and kirchoff
i1R1+i2R2=e
i3R3+i4R4=e
I1R1+I5R5-I3R3=0
i2R2-i4R4-I5R5=0
i1-i2-15=0
i3+i5-i4=0
Now to solve
2007-06-25 05:26:33 · answer #1 · answered by odu83 7 · 0⤊ 0⤋
You have 5 unknowns, so you need 5 equations to solve. The five equations are:
9=2(i1)+2(i2)+3(i3)+7(i4)+4(i5)
i=i1+i3
i1=i5+i3
i3=i4-i5
i=i2+i4
Plug into your calculators System of Equations function to solve.
2007-06-25 05:26:28 · answer #2 · answered by Not Eddie Money 3 · 0⤊ 0⤋